Java program to check whether a number is even or odd

I wrote this Java program to check whether a number is even or odd using the modulo operator. Is this the correct and efficient approach, or is there a better way to implement this in Java?

class EvenOddCheck {
   public static void main(String[] args) {
       int num = 42;

       if (num % 2 == 0) {
           System.out.println(num + " is Even");
       } else {
           System.out.println(num + " is Odd");
       }
   }
}

Look, I wrapped your code into code tags, and representation of it looks much better  ..use Code button when posting code.
class EvenOddCheck {    public static void main(String[] args) {        int num = 42;        if (num % 2 == 0) {            System.out.println(num + " is Even");        } else {            System.out.println(num + " is Odd");        }    } }

Yoga Vignesshwar Venkatsan wrote:Is this the correct... approach

Well, you could run your program though various inputs and verify output(s) with your own manual calculations in your head. See if you could arrive at some conclusions yourself first.

When testing, try to test not just what one would call 'habitual' inputs, but also some less expected, i.e. 1, 0; -3;

See what you get.

Yoga Vignesshwar Venkatsan wrote:Is this the... efficient approach

There is no definite answer to that. More like, is this efficient enough to your needs? Likely yes. There are some other ways of doing this, I think more efficient, but certainly less known and understood. i.e. use condition if ((num & 1) == 0). Try to research why.

It's efficient enough. Probably 99.999% of the time to run this code is required to run System.out and no amount of tinkering is going to reduce the remaining 0.001% noticeably.