Grant:
Interesting qstn......
But praatically do you think this has any
use at all!
Anyways, if you implement the show() interface,
you are overwriting the show() method from the
parent. Hence, the show() method that you implemented
is the one which is executed.
On the contrary, you could do this also:
- donot implement the interface explecitly. It is
assumed that the interface is implemented since, the
parent class implements it. I din't think this would
work till I ran....was very interesting though....
chk this out.....
regds.

- satya