Call a method in super's super class??

Hi Folks,

1) Class A is the Super class and B extends from A
2) Class C extends B
3) The method display has been over-ridden in all the classes.
4) From the method in class C, I wish to call that of B & A.
5) I am able to call that of B using super.

Question: Is there a way to call A's display from C's display directly???

class A { public void display() { System.out.println("Display of Class A called"); } } class B extends A { public void display() { System.out.println("Display of Class B called"); } } class C extends B { public void display() { System.out.println("Display of Class C called"); super.display(); // calls B's Display [B] // Is there a way to call A's Display from here???[/B] } } public class TestArrayList { public static void main(String [] args) { A a1 = new C(); a1.display(); } }

Originally posted by sivakumar k r:
Is there a way to call A's display from C's display directly

No.

Hi,

class C extends B {
public void display() {
new A().display(); // call like this
System.out.println("Display of Class C called");
super.display(); // calls B's Display
}}
}
}

bye for now
sat

Class C = A + B + delta C.
I wanted to call C's --> A's display.

I didn't want to call display by simply create an object of A and calling the method from that newly created object within C.

Originally posted by sivakumar k r:
I didn't want to call display by simply create an object of A and calling the method from that newly created object within C.

Unfortunately, the answer is still "no".

Think of it like this. You are the designer of class C, which inherits from B. Your class overrides B, and implements new functionality. But one of the reasons why you override certain methods is that some of the methods of B, are no longer valid, for your C class -- you need those objects overriden, or your class will not function correctly.

Now... do you really want some other developer to create a D class which subclasses your C class, and bypasses the method calls that you overriden?

Henry
[ February 08, 2007: Message edited by: Henry Wong ]

I wouldn't say that it's "unfortunate".

The whole desire to call a "super's super method" is an indication that you should rethink your design. There probably is an abstraction missing or something that would obliterate that need.