Inheritance and Serialization

If super-class is not serializable but subclass is serializable
1. The super class must have no argument constructor accessible to subclass.
2. This constructor will be used to initialize subclass' sub-object.


please explain above statement.

import java.io.*; class SuperClass { public SuperClass() { System.out.println("SuperClass() called"); } public SuperClass(int i) { System.out.println("SuperClass(" + i + ") called"); } } class SubClass extends SuperClass implements Serializable { public SubClass(int i) { super(i); System.out.println("SubClass(" + i + ") called"); } } public class Test { public static void main(String[] args) throws Exception { SubClass sub1 = new SubClass(13); // two lines are printed // serialize ByteArrayOutputStream baos = new ByteArrayOutputStream(); ObjectOutputStream oos = new ObjectOutputStream(baos); oos.writeObject(sub1); oos.close(); byte[] data = baos.toByteArray(); System.out.println("---"); // deserialize ByteArrayInputStream bais = new ByteArrayInputStream(data); ObjectInputStream ois = new ObjectInputStream(bais); SubClass sub2 = (SubClass)ois.readObject(); // only one line is printed } }Try this code. After that remove the first constructor of SuperClass and try again.

hey thanks rob for your solution... Now i got the point....

You're welcome