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<head><title>3sum closest</title>
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<h2>Yanzhan's solution for "3sum closest"</h2>
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<li>Hi, I'm Yanzhan. For more algothmic problems, visit my Youtube Channel <a href="https://www.youtube.com/channel/UCDkz-__gl3frqLexukpG0DA?view_as=subscriber" target=_blank>[Yanzhan Yang's Youtube Channel]</a> or my Twitter Account <a href="https://twitter.com/YangYanzhan" target=_blank>[Yanzhan Yang's Twitter]</a> or my GitHub HomePage <a href="https://github.com/yangyanzhan/code-camp" target=_blank>[Yanzhan Yang's GitHub Project]</a> .</li>
<li>It's fascinating to solve algothmic problems, follow Yanzhan to learn more!</li>
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<h3>
solution:
</h3>
<pre class="yanzhan-hidden"><code class="c++">class Solution {
public:
int threeSumClosest(vector<int> &nums, int target) {
int n = nums.size();
sort(nums.begin(), nums.end());
int res = 0, min_gap = numeric_limits<int>::max();
for (int i = 0; i <= n - 3; i++) {
int a = nums[i];
int j = i + 1, k = n - 1;
while (j < k) {
int b = nums[j], c = nums[k];
int sum = a + b + c;
int gap = sum - target;
int abs_gap = abs(gap);
if (abs_gap < min_gap) {
res = sum;
min_gap = abs_gap;
}
if (gap == 0) {
return res;
} else if (gap > 0) {
k--;
} else {
j++;
}
}
}
return res;
}
};
</code></pre>
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