/**
 * 
 */
package coding.bat.solutions;

/**
 * @author Aman Shekhar
 *
 */
public class StringOne {

	/**
	 * @param args
	 */
	public static void main(String[] args) {

	}

	// Given a string name, e.g. "Bob", return a greeting of the form "Hello Bob!".
	//
	//
	// helloName("Bob") → "Hello Bob!"
	// helloName("Alice") → "Hello Alice!"
	// helloName("X") → "Hello X!"

	public String helloName(String name) {
		return "Hello " + name + "!";
	}

	// --------------------------------------------------------------------------------------------

	// Given two strings, a and b, return the result of putting them together in the
	// order abba, e.g. "Hi" and "Bye" returns "HiByeByeHi".
	//
	//
	// makeAbba("Hi", "Bye") → "HiByeByeHi"
	// makeAbba("Yo", "Alice") → "YoAliceAliceYo"
	// makeAbba("What", "Up") → "WhatUpUpWhat"

	public String makeAbba(String a, String b) {
		return a + b + b + a;
	}

	// --------------------------------------------------------------------------------------------

	// The web is built with HTML strings like "<i>Yay</i>" which draws Yay as
	// italic text. In this example, the "i" tag makes <i> and </i> which surround
	// the word "Yay". Given tag and word strings, create the HTML string with tags
	// around the word, e.g. "<i>Yay</i>".
	//
	//
	// makeTags("i", "Yay") → "<i>Yay</i>"
	// makeTags("i", "Hello") → "<i>Hello</i>"
	// makeTags("cite", "Yay") → "<cite>Yay</cite>"

	public String makeTags(String tag, String word) {
		return "<" + tag + ">" + word + "</" + tag + ">";
	}

	// --------------------------------------------------------------------------------------------

	// Given an "out" string length 4, such as "<<>>", and a word, return a new
	// string where the word is in the middle of the out string, e.g. "<<word>>".
	// Note: use str.substring(i, j) to extract the String starting at index i and
	// going up to but not including index j.
	//
	//
	// makeOutWord("<<>>", "Yay") → "<<Yay>>"
	// makeOutWord("<<>>", "WooHoo") → "<<WooHoo>>"
	// makeOutWord("[[]]", "word") → "[[word]]"
	//
	public String makeOutWord(String out, String word) {
		String firstPart = out.substring(0, 2);
		String secondPart = out.substring(2, 4);
		return firstPart + word + secondPart;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a new string made of 3 copies of the last 2 chars of
	// the original string. The string length will be at least 2.
	//
	//
	// extraEnd("Hello") → "lololo"
	// extraEnd("ab") → "ababab"
	// extraEnd("Hi") → "HiHiHi"

	public String extraEnd(String str) {
		if (str.length() > 2) {
			String mResult = str.substring(str.length() - 2, str.length());
			return mResult + mResult + mResult;
		}
		return str + str + str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return the string made of its first two chars, so the String
	// "Hello" yields "He". If the string is shorter than length 2, return whatever
	// there is, so "X" yields "X", and the empty string "" yields the empty string
	// "". Note that str.length() returns the length of a string.
	//
	//
	// firstTwo("Hello") → "He"
	// firstTwo("abcdefg") → "ab"
	// firstTwo("ab") → "ab"

	public String firstTwo(String str) {
		if (str.length() > 2)
			return str.substring(0, 2);
		return str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string of even length, return the first half. So the string "WooHoo"
	// yields "Woo".
	//
	//
	// firstHalf("WooHoo") → "Woo"
	// firstHalf("HelloThere") → "Hello"
	// firstHalf("abcdef") → "abc"

	public String firstHalf(String str) {
		int length = str.length() / 2;
		return str.substring(0, length);
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a version without the first and last char, so "Hello"
	// yields "ell". The string length will be at least 2.
	//
	//
	// withoutEnd("Hello") → "ell"
	// withoutEnd("java") → "av"
	// withoutEnd("coding") → "odin"

	public String withoutEnd(String str) {
		return str.substring(1, str.length() - 1);
	}

	// --------------------------------------------------------------------------------------------

	// Given 2 strings, a and b, return a string of the form short+long+short, with
	// the shorter string on the outside and the longer string on the inside. The
	// strings will not be the same length, but they may be empty (length 0).
	//
	//
	// comboString("Hello", "hi") → "hiHellohi"
	// comboString("hi", "Hello") → "hiHellohi"
	// comboString("aaa", "b") → "baaab"
	//
	public String comboString(String a, String b) {
		if (a.length() > b.length())
			return b + a + b;
		return a + b + a;
	}

	// --------------------------------------------------------------------------------------------

	// Given 2 strings, return their concatenation, except omit the first char of
	// each. The strings will be at least length 1.
	//
	//
	// nonStart("Hello", "There") → "ellohere"
	// nonStart("java", "code") → "avaode"
	// nonStart("shotl", "java") → "hotlava"

	public String nonStart(String a, String b) {
		return a.substring(1, a.length()) + b.substring(1, b.length());
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a "rotated left 2" version where the first 2 chars are
	// moved to the end. The string length will be at least 2.
	//
	//
	// left2("Hello") → "lloHe"
	// left2("java") → "vaja"
	// left2("Hi") → "Hi"
	//
	public String left2(String str) {
		return str.substring(2, str.length()) + str.substring(0, 2);
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a "rotated right 2" version where the last 2 chars are
	// moved to the start. The string length will be at least 2.
	//
	//
	// right2("Hello") → "loHel"
	// right2("java") → "vaja"
	// right2("Hi") → "Hi"
	//
	public String right2(String str) {
		int len = str.length() - 2;
		return (str.substring(len) + str.substring(0, len));
	}

	// --------------------------------------------------------------------------------------------

	//
	// Given a string, return a string length 1 from its front, unless front is
	// false, in which case return a string length 1 from its back. The string will
	// be non-empty.
	//
	//
	// theEnd("Hello", true) → "H"
	// theEnd("Hello", false) → "o"
	// theEnd("oh", true) → "o"

	public String theEnd(String str, boolean front) {
		if (front)
			return str.substring(0, 1);
		return str.substring(str.length() - 1, str.length());
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a version without both the first and last char of the
	// string. The string may be any length, including 0.
	//
	//
	// withouEnd2("Hello") → "ell"
	// withouEnd2("abc") → "b"
	// withouEnd2("ab") → ""

	public String withouEnd2(String str) {
		if (str.length() >= 3)
			return str.substring(1, str.length() - 1);
		return "";
	}

	// --------------------------------------------------------------------------------------------

	// Given a string of even length, return a string made of the middle two chars,
	// so the string "string" yields "ri". The string length will be at least 2.
	//
	//
	// middleTwo("string") → "ri"
	// middleTwo("code") → "od"
	// middleTwo("Practice") → "ct"

	public String middleTwo(String str) {
		int halfLength = (str.length() / 2) - 1;
		return str.substring(halfLength, halfLength + 2);
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return true if it ends in "ly".
	//
	//
	// endsLy("oddly") → true
	// endsLy("y") → false
	// endsLy("oddy") → false

	public boolean endsLy(String str) {
		if (str.length() < 2)
			return false;
		return str.substring(str.length() - 2).equals("ly");
	}

	// --------------------------------------------------------------------------------------------

	// Given a string and an int n, return a string made of the first and last n
	// chars from the string. The string length will be at least n.
	//
	//
	// nTwice("Hello", 2) → "Helo"
	// nTwice("Chocolate", 3) → "Choate"
	// nTwice("Chocolate", 1) → "Ce"

	public String nTwice(String str, int n) {
		return str.substring(0, n) + str.substring(str.length() - n, str.length());
	}

	// --------------------------------------------------------------------------------------------

	// Given a string and an index, return a string length 2 starting at the given
	// index. If the index is too big or too small to define a string length 2, use
	// the first 2 chars. The string length will be at least 2.
	//
	//
	// twoChar("java", 0) → "ja"
	// twoChar("java", 2) → "va"
	// twoChar("java", 3) → "ja"

	public String twoChar(String str, int index) {
		if (index <= str.length() - 2 && index >= 0)
			return str.substring(index, index + 2);
		return str.substring(0, 2);
	}

	// --------------------------------------------------------------------------------------------

	// Given a string of odd length, return the string length 3 from its middle, so
	// "Candy" yields "and". The string length will be at least 3.
	//
	//
	// middleThree("Candy") → "and"
	// middleThree("and") → "and"
	// middleThree("solving") → "lvi"

	public String middleThree(String str) {
		int length = str.length() / 2;
		return str.substring(length - 1, length + 2);
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return true if "bad" appears starting at index 0 or 1 in the
	// string, such as with "badxxx" or "xbadxx" but not "xxbadxx". The string may
	// be any length, including 0. Note: use .equals() to compare 2 strings.
	//
	//
	// hasBad("badxx") → true
	// hasBad("xbadxx") → true
	// hasBad("xxbadxx") → false
	//
	public boolean hasBad(String str) {
		if (str.length() == 3 && str.equals("bad"))
			return true;
		if (str.length() >= 4) {
			return (str.substring(0, 3).equals("bad") || str.substring(1, 4).equals("bad"));
		}
		return false;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a string length 2 made of its first 2 chars. If the
	// string length is less than 2, use '@' for the missing chars.
	//
	//
	// atFirst("hello") → "he"
	// atFirst("hi") → "hi"
	// atFirst("h") → "h@"
	//

	public String atFirst(String str) {
		if (str.length() == 0)
			return "@@";
		if (str.length() < 2)
			return str.substring(0, 1) + "@";
		return str.substring(0, 2);
	}

	// --------------------------------------------------------------------------------------------

	// Given 2 strings, a and b, return a new string made of the first char of a and
	// the last char of b, so "yo" and "java" yields "ya". If either string is
	// length 0, use '@' for its missing char.
	//
	//
	// lastChars("last", "chars") → "ls"
	// lastChars("yo", "java") → "ya"
	// lastChars("hi", "") → "h@"

	public String lastChars(String a, String b) {
		if (a.length() == 0 && b.length() == 0)
			return "@@";
		if (a.length() == 0) {
			return "@" + b.charAt(b.length() - 1);
		} else if (b.length() == 0) {
			return a.charAt(0) + "@";
		}
		return a.substring(0, 1) + b.substring(b.length() - 1);
	}

	// --------------------------------------------------------------------------------------------

	// Given two strings, append them together (known as "concatenation") and return
	// the result. However, if the concatenation creates a double-char, then omit
	// one of the chars, so "abc" and "cat" yields "abcat".
	//
	//
	// conCat("abc", "cat") → "abcat"
	// conCat("dog", "cat") → "dogcat"
	// conCat("abc", "") → "abc"

	public String conCat(String a, String b) {
		if (a.length() >= 1 && b.length() >= 1) {
			if (a.charAt(a.length() - 1) == (b.charAt(0))) {
				return a + b.substring(1, b.length());
			}
		}
		return a + b;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string of any length, return a new string where the last 2 chars, if
	// present, are swapped, so "coding" yields "codign".
	//
	//
	// lastTwo("coding") → "codign"
	// lastTwo("cat") → "cta"
	// lastTwo("ab") → "ba"

	public String lastTwo(String str) {
		if (str.length() >= 2) {
			return str.substring(0, str.length() - 2) + str.charAt(str.length() - 1) + str.charAt(str.length() - 2);
		}
		return str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, if the string begins with "red" or "blue" return that color
	// string, otherwise return the empty string.
	//
	//
	// seeColor("redxx") → "red"
	// seeColor("xxred") → ""
	// seeColor("blueTimes") → "blue"

	public String seeColor(String str) {
		if (str.length() == 3) {
			if (str.substring(0, 3).equals("red"))
				return "red";
			return "";
		}
		if (str.length() >= 4) {
			if (str.substring(0, 4).equals("blue"))
				return "blue";
			if (str.substring(0, 3).equals("red"))
				return "red";
			return "";
		}
		return "";
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return true if the first 2 chars in the string also appear at
	// the end of the string, such as with "edited".
	//
	//
	// frontAgain("edited") → true
	// frontAgain("edit") → false
	// frontAgain("ed") → true

	public boolean frontAgain(String str) {
		int mLength = str.length();
		if (mLength >= 2) {
			return str.substring(0, 2).equals(str.substring(mLength - 2, mLength));
		}
		return false;
	}

	// --------------------------------------------------------------------------------------------

	// Given two strings, append them together (known as "concatenation") and return
	// the result. However, if the strings are different lengths, omit chars from
	// the longer string so it is the same length as the shorter string. So "Hello"
	// and "Hi" yield "loHi". The strings may be any length.
	//
	//
	// minCat("Hello", "Hi") → "loHi"
	// minCat("Hello", "java") → "ellojava"
	// minCat("java", "Hello") → "javaello"

	public String minCat(String a, String b) {
		int lenA = a.length();
		int lenB = b.length();
		if (lenA >= lenB)
			return (a.substring(lenA - lenB) + b);
		else
			return (a + b.substring(lenB - lenA));
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a new string made of 3 copies of the first 2 chars of
	// the original string. The string may be any length. If there are fewer than 2
	// chars, use whatever is there.
	//
	//
	// extraFront("Hello") → "HeHeHe"
	// extraFront("ab") → "ababab"
	// extraFront("H") → "HHH"
	//

	public String extraFront(String str) {
		if (str.length() >= 2) {
			String mSubString = str.substring(0, 2);
			return mSubString + mSubString + mSubString;
		}
		return str + str + str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, if a length 2 substring appears at both its beginning and
	// end, return a string without the substring at the beginning, so "HelloHe"
	// yields "lloHe". The substring may overlap with itself, so "Hi" yields "".
	// Otherwise, return the original string unchanged.
	//
	//
	// without2("HelloHe") → "lloHe"
	// without2("HelloHi") → "HelloHi"
	// without2("Hi") → ""

	public String without2(String str) {
		int mLength = str.length();
		if (mLength >= 2) {
			if (str.substring(0, 2).equals(str.substring(mLength - 2, mLength))) {
				return str.substring(2, str.length());
			}
			return str;
		}
		return str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, return a version without the first 2 chars. Except keep the
	// first char if it is 'a' and keep the second char if it is 'b'. The string may
	// be any length. Harder than it looks.
	//
	//
	// deFront("Hello") → "llo"
	// deFront("java") → "va"
	// deFront("away") → "aay"

	public String deFront(String str) {
		if ((str.length() == 1) && (str.charAt(0) == 'a')) {
			return "a";
		} else if (str.charAt(0) == 'a') {
			if (str.charAt(1) == 'b') {
				return str;
			}
			return "a" + str.substring(2, str.length());
		} else if (str.charAt(1) == 'b') {
			return "b" + str.substring(2, str.length());
		}
		return str.substring(2, str.length());
	}

	// --------------------------------------------------------------------------------------------

	// Given a string and a second "word" string, we'll say that the word matches
	// the string if it appears at the front of the string, except its first char
	// does not need to match exactly. On a match, return the front of the string,
	// or otherwise return the empty string. So, so with the string "hippo" the word
	// "hi" returns "hi" and "xip" returns "hip". The word will be at least length
	// 1.
	//
	//
	// startWord("hippo", "hi") → "hi"
	// startWord("hippo", "xip") → "hip"
	// startWord("hippo", "i") → "h"

	public String startWord(String str, String word) {
		int lenStr = str.length();
		int lenWord = word.length();
		String temp;
		if (lenStr >= lenWord) {
			temp = str.substring(1, lenWord);
			if (word.substring(1).equals(temp))
				return (str.charAt(0) + temp);
			return "";
		}
		return "";
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, if the first or last chars are 'x', return the string without
	// those 'x' chars, and otherwise return the string unchanged.
	//
	//
	// withoutX("xHix") → "Hi"
	// withoutX("xHi") → "Hi"
	// withoutX("Hxix") → "Hxi"

	public String withoutX(String str) {
		int len = str.length();
		if (len >= 2) {
			char ch = str.charAt(0);
			StringBuilder stbuild = new StringBuilder(len);
			if (ch != 'x')
				stbuild.append(ch);
			stbuild.append(str.substring(1, len - 1));
			ch = str.charAt(len - 1);
			if (ch != 'x')
				stbuild.append(ch);
			return stbuild.toString();
		} else if (len == 1 && str.charAt(0) == 'x')
			return "";
		else
			return str;
	}

	// --------------------------------------------------------------------------------------------

	// Given a string, if one or both of the first 2 chars is 'x', return the string
	// without those 'x' chars, and otherwise return the string unchanged. This is a
	// little harder than it looks.
	//
	//
	// withoutX2("xHi") → "Hi"
	// withoutX2("Hxi") → "Hi"
	// withoutX2("Hi") → "Hi"

	public String withoutX2(String str) {
		int len = str.length();
		if (len == 0)
			return str;
		if (len == 1 && str.charAt(0) == 'x')
			return "";
		if (len >= 2) {
			if (str.charAt(0) == 'x') {
				if (str.charAt(1) != 'x')
					return str.substring(1, len);
				if (str.charAt(1) == 'x')
					return str.substring(2, len);
			} else if (str.charAt(1) == 'x') {
				return str.charAt(0) + str.substring(2, len);
			}
		}
		return str;
	}

	// --------------------------------------------------------------------------------------------

}