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CWG2873 [over.over] Is it intended that when a function is overloaded with a function template then its address cannot be taken unambiguously #516

Description

@ranaanoop

Full name of submitter: Anoop Rana

Reference (section label): [over.over]

Link to reflector thread (if any): https://stackoverflow.com/questions/78170991/in-c-why-cant-i-take-the-address-of-a-function-that-also-has-a-templated-vers

Issue description:

I came across the following code that is rejected by all three compilers and seems to be ill-formed as per current wording in over.over#3.

template <typename T>
void AcceptAnything(T&&);

void Foo();

template <typename T>
void Foo();

void Bar() {
  AcceptAnything(&Foo);
}

I think this is ill-formed because(as explained here) because the specialization from the function template cannot be formed here so nothing can be added to the set and so it is ill-formed(I may be wrong here but as far as I understand the topic this is what makes it ill-formed). But I don't think the whole program should be ill-formed here as there is another non-template function available that can be used. Instead this inability to form a specialization from the function template can be ignored as a non-template function that can be used is available.

Suggested resolution:

Maybe something like the following can be added:

The program is ill-formed if this is part of the final result of overload resolution.

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