Write a Python program that will figure out all the different combinations of pennies, nickels, dimes, and quarters in a given `value` provided as a single positional argument. The value must be greater than 0 and less than or equal to 100.

import argparse

from itertools import product

from functools import partial

def get_args():

"""Get command-line arguments"""

parser = argparse.ArgumentParser(

description='Coin combos for value',

formatter_class=argparse.ArgumentDefaultsHelpFormatter)

parser.add_argument('value', metavar='int', type=int, help='Sum')

args = parser.parse_args()

if not 0 < args.value <= 100:

parser.error('value "{}" must be > 1 and <= 100'.format(args.value))

return args

def main():

"""Make a jazz noise here"""

args = get_args()

value = args.value

nickels = range((value // 5) + 1)

dimes = range((value // 10) + 1)

quarters = range((value // 25) + 1)

fig = partial(figure, value)

combos = [c for c in map(fig, product(nickels, dimes, quarters)) if c]

print('If you give me {} cent{}, I can give you:'.format(

value, '' if value == 1 else 's'))

for i, combo in enumerate(combos, 1):

print('{:3}: {}'.format(i, fmt_combo(combo)))

def fmt_combo(combo):

"""English version of combo"""

out = []

for coin, val in zip(('quarter', 'dime', 'nickel', 'penny'), combo):

if val:

plural = 'pennies' if coin == 'penny' else coin + 's'

out.append('{} {}'.format(val, coin if val == 1 else plural))

return ', '.join(out)

def figure(value, coins):

"""

nickels, dimes, quarters = coins

big_coins = (5 * nickels) + (10 * dimes) + (25 * quarters)

if big_coins <= value:

return (quarters, dimes, nickels, value - big_coins)

if __name__ == '__main__':

main()