[Python-Dev] Go \x yourself

[Ka-Ping Yee]

On Thu, 3 Aug 2000, Tim Peters wrote:
> 
> >>> "\x123465" # \x12 -> \022, "3456" left alone
> '\0223456'
> >>> "\x65"
> 'e'
> >>> "\x1"
> ValueError
> >>> "\x\x"
> ValueError
> >>>

I'm quite certain that this should be a SyntaxError, not a ValueError:

    >>> "\x1"
    SyntaxError: two hex digits are required after \x
    >>> "\x\x"
    SyntaxError: two hex digits are required after \x

Otherwise, +1.  Sounds great.


-- ?!ng