a splitting headache

[Paul Rubin]

Mensanator <mensanator at aol.com> writes:
> Thanks, but what I wanted was
> ['00','1','0','1','0','1111','00','1','0' '1'].

    >>> c = '001010111100101'
    >>> list(''.join(g) for k,g in groupby(c))
    ['00', '1', '0', '1', '0', '1111', '00', '1', '0', '1']

is really not that unnatural.