spilt question

[Chris Angelico]

On Fri, May 17, 2013 at 1:00 AM, loial <jldunn2000 at gmail.com> wrote:
> I want to split a string so that I always return everything BEFORE the LAST underscore
>
> HELLO_xxxxxxxx.lst         # should return HELLO
> HELLO_GOODBYE_xxxxxxxx.ls  # should return HELLO_GOODBYE
>
> I have tried with rsplit but cannot get it to work.
>
> Any help appreciated

Try with a limit:

>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)
['HELLO_GOODBYE', 'xxxxxxxx.ls']
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)[0]
'HELLO_GOODBYE'

You can easily get docs on it:

>>> help("".rsplit)
Help on built-in function rsplit:

rsplit(...)
    S.rsplit(sep=None, maxsplit=-1) -> list of strings

    Return a list of the words in S, using sep as the
    delimiter string, starting at the end of the string and
    working to the front.  If maxsplit is given, at most maxsplit
    splits are done. If sep is not specified, any whitespace string
    is a separator.

ChrisA