How to call the stored values

[Dieselkaine]

Complete beginner
I don't know how to get the player choice to return the values stored in alpha

### The idea is to have the player play against the computer without knowing the values of their choices 
### then to guess the high middle low choice

import random

def alpha(*values):
    alpha.values = values or alpha.values
    return alpha.values
alpha.values =()

def bravo(*values):
    bravo.values = values or bravo.values
    return bravo.values
bravo.values =()

alpha(5, 3, 2)
a, b, c = alpha()

bravo(2, 5, 3)
d, e, f = bravo()

def choice():
    choice = ""
    while choice != "a" and choice != "b" and choice != "c":
        print ("choose a, b or c")
        choice = input()
    print (choice) 

    return str(choice)

def check(choice):
    compmove = (d, e, f)
    comp = random.choice (compmove)
    print (comp) 
    
    
    if (choice) == str(comp):
            print("draw")
            print (choice) 
            print (comp)

    elif (choice) > str(comp):
            print ("player")
            print (choice)
            print (comp)
                    
    elif (choice) < str (comp):
            print ("comp")
            print (choice)
            print (comp)

def loop():
    guesses = 0
    while guesses < 6:
        move = choice()
        check(move)
        guesses = guesses +1

loop()

[ichabod801]

It's not clear to me at all what you are trying to do, but if you want the values stored in alpha, you either need to call alpha or reference alpha.values.

[gontajones]

if (choice) == str(comp):

If the player inputs 'a', inside check() are comparing 2 single chars (eg 'a' and '3').
Maybe you can use a dictionary to get the number of the letter coming from input()

[Dieselkaine]

in the above code a = 5 just like e = 5
print (a + e) would give you 10
but when it prints the player choice a, it will return a
but when it prints the comp choice e, it will print 5
I want to convert the player choice back into the integer stored in alpha
so it can evaluate them correctly in the check block

hope that explains it better

[gontajones]

I tried to keep your logic.

# The idea is to have the player play against the computer without knowing the values of their choices
# then to guess the high middle low choice

import random

d_moves = {}


def alpha(**kwargs):
    if(d_moves):
        # Merge if d_moves already exists
        return {**d_moves, **kwargs}
    return kwargs


#def bravo(*values):
#    bravo.values = values or bravo.values
#    return bravo.values
#bravo.values =()


d_moves = alpha(a=5, b=3, c=2)
d_moves = alpha(d=2, e=5, f=3)


def choice():
    choice = ""
    while choice != "a" and choice != "b" and choice != "c":
        print("choose a, b or c")
        choice = input()

    # Get the int using a,b,c as key of the dict
    choice = d_moves[choice]
    return choice


def check(choice):
    compmove = ('d', 'e', 'f')
    comp = random.choice(compmove)
    comp = d_moves[comp]

    if (choice) == (comp):
        print("draw")
        print(choice)
        print(comp)

    elif (choice) > (comp):
        print("player")
        print(choice)
        print(comp)

    elif (choice) < (comp):
        print("comp")
        print(choice)
        print(comp)


def loop():
    guesses = 0
    while guesses < 6:
        move = choice()
        check(move)
        guesses = guesses + 1


loop()

[Dieselkaine]

Cool that does do what i wanted
Now if only i could understand why XD

[gontajones]

You can use a dictionary directly.
Work with dictionaries in python is very important.

d_moves = {'a': 5, 'b': 3, 'c': 2, 'd': 2, 'e': 5, 'f': 3}
# To access a value of a key: d[key] = value
print(d_moves['a']) # <- prints 5