How can I return my list from a func?

[Mike Ru]

I have a list. I'm getting items that starting from number.

s = ['kdkkd', '1 america', 'wwww', '2 Russia', 'd333', '3England']
def get_title_list(a):
    for x in mylist:
        try:
            int(x[0])
            print(x)
        except ValueError:
            pass
get_title_list(s)

It works, but it doesn't work if I'm trying like this

s = ['kdkkd', '1 america', 'wwww', '2 Russia', 'd333', '3England']
def get_title_list(a):
    for x in mylist:
        try:
            int(x[0])
            return x
        except ValueError:
            pass
print(get_title_list(s))

I get one itme from s. How to return?

[buran]

you need to construct the filtered list before returning from function. At the moment you return after first item that starts with digit.

s = ['kdkkd', '1 america', 'wwww', '2 Russia', 'd333', '3England']

def get_title_list(my_list):
    filtered = []
    for item in my_list:
        try:
            int(item[0])
            filtered.append(item)
        except ValueError:
            pass
    return filtered
print(get_title_list(s))

This is your code with minimal changes. Here are some more examples. Even your code can be changed to not use int conversion.

using comprehension

import string
def get_title_list(my_list):
    return [item for item in my_list if item[0] in string.digits]

using filter

import string
def get_title_list(my_list):
    return filter(lambda x: x[0] in string.digits, my_list)

[snippsat]

Another way is to yield instead of return.
Then make it list() outside of function or can also iterate over it.

def get_title(lst):
    for x in lst:
        try:
            int(x[0])
            yield x
        except ValueError:
            pass

if __name__ == '__main__':
    lst = ['kdkkd', '1 america', 'wwww', '2 Russia', 'd333', '3England']
    print(list(get_title(lst)))

Output:
['1 america', '2 Russia', '3England']

>>> for item in get_title(lst):
...     print(item)
...     
1 america
2 Russia
3England

[buran]

@snippsat post actually reminded me that in python3 filter would return filter object, so if you want a list you need to explicitly convert it

import string
def get_title_list(my_list):
    return list(filter(lambda x: x[0] in string.digits, my_list))

or you need to iterate over like in snippsat's example

s = ['kdkkd', '1 america', 'wwww', '2 Russia', 'd333', '3England']
import string
def get_title_list(my_list):
    return filter(lambda x: x[0] in string.digits, my_list)

for item in get_title_list(s):
    print(item)

---

further on, because of recent discussion on PEP8 compliance and because PEP8 does recommend using str.starstwith method instead of slicing/indexing when check for prefix (same for str.endswith and checking for suffix). e.g.

import string
digits =  tuple(string.digits)
def get_title_list(my_list):
    return [item for item in my_list if item.startswith(digits)]