Unable to open file

[ayaz786amd]

Hi
the code is

 print("a file")
text_file = open('123.txt','r')

print(text_file.read())

text_file.close()

but its not opening the file. just showing [Finished in 0.2s] in console. I am using sublime text

[Larz60+]

FYI: print statement is indented 1 character, This should give you a syntax error

[buran]

are you sure 123.txt is not an empty file with nothing in it?

[ayaz786amd]

there is no syntax error.

Yes 123.txt is not empty file and its placed in the same folder as python file.

This python settings is a headache more difficult than understanding code

[Larz60+]

when I run your code as posted, it produces a syntax error (as it should with line 1 indented 1 character)
Is the posted code exactly what you are running
modify code as follows and try again:

import os

# make sure running in proper directory
os.chdir(os.path.abspath(os.path.dirname(__file__)))

print("a file")
text_file = open('123.txt','r')
 
print(text_file.read())
 
text_file.close()

better:

import os

# make sure running in proper directory
os.chdir(os.path.abspath(os.path.dirname(__file__)))

print("a file")
with open('123.txt','r') as fp:
    print(text_file.read())

[ayaz786amd]

i think there is nothing wrong with code because all the suggested codes are giving same output [Finished in s]. There may be something i didnt installed properly or have some issue with sublime text editor i am using

[micseydel]

What happens if you run the script with a regular shell rather than Sublime?

[ayaz786amd]

it immediately print

 print("a file")

:D