dictionary, list and iteration

[Annie]

a = {7: 0.1, 8: 0.2, 11: 0.1, 12:0.2, 13:0.1, 14: 0.2}
b = [   100,              200,             300         ]
c = {}

expected result 
c = {7: 100,         11:200,          13:300}

I want to replace the   values of a with odd number keys   with a new list b consecutively, 
and output c with the new value having odd number keys in a, is there any short way to do it ?

[buran]

a = {7: 0.1, 8: 0.2, 11: 0.1, 12:0.2, 13:0.1, 14:0.2}
b = [100, 200, 300]
c = {key:b[i] for i, key in enumerate(sorted([k for k in a.keys() if k%2]))}
print c

for sake of readability you may prefer

a = {7: 0.1, 8: 0.2, 11: 0.1, 12:0.2, 13:0.1, 14:0.2}
b = [100, 200, 300]
c={}
sorted_odd_keys = sorted([k for k in a.keys() if k%2])
for i, key in enumerate(sorted_odd_keys):
    c[key] = b[i]
print c

or my favorite:

a = {7: 0.1, 8: 0.2, 11: 0.1, 12:0.2, 13:0.1, 14:0.2}
b = [100, 200, 300]
sorted_odd_keys = sorted([k for k in a.keys() if k%2])
c = dict(zip(sorted_odd_keys, b))
print c

[Annie]

Thanks a lot !