Replace characters from file in Python 2.7

[melmouja]

Hello

I can't replace more strings from file, i use two ways:

• function lambda
  
• expr regulier
  

#! /bin/python
import re
import sys
import fileinput
import os
stripped = lambda s: "".join(i for i in s if 31 < ord(i) < 127)
#en dur ça marche
print(stripped('\xe2\x80\x9chttp://www.google.com\xe2\x80\x9d blah blah#%#@$^blah'))
 
for line in fileinput.input('fic.txt'):
    #with exrp regu
    line1 = re.sub(r'[^\x00-\x7f]', r'', line.rstrip())
    print(line1)
    ####################
    #with lambda
    print(stripped(line.rstrip()))

Output:
>cat fic.txt
\xe2\x80\x9chttp://www.google.com\xe2\x80\x9d blah blah#%#@$^blah

Thanks for help

[ichabod801]

What exactly are you trying to do? I'm not sure what result you are trying to get.

[melmouja]

Hello,
I use three methods to replace "\xe2\x80\x9c and" "\xe2\x80\x9d" :
The first give me a good result

stripped = lambda s: "".join(i for i in s if 31 < ord(i) < 127)
#en dur ça marche
print(stripped('\xe2\x80\x9chttp://www.google.com\xe2\x80\x9d blah blah#%#@$^blah'))

Output:
http://www.google.com blah blah#%#@$^blah

but the others not ok

for line in fileinput.input('fic.txt'):
    #with exrp regu
    line1 = re.sub(r'[^\x00-\x7f]', r'', line.rstrip())
    print(line1)
    ####################
    #with lambda
    print(stripped(line.rstrip()))

Output:
\xe2\x80\x9chttp://www.google.com\xe2\x80\x9d blah blah#%#@$^blah
\xe2\x80\x9chttp://www.google.com\xe2\x80\x9d blah blah#%#@$^blah

I thank it's clear now.

Thanks for help