Return not vowels list

[erfanakbari1]

Hey there !
Since today , I've been trying to write a program doing this thing below :

'''
Create a program that takes some text and returns a list of all the characters in the text that are not vowels,
sorted in alphabetical order

and using some sets in it . 
'''

I actually tried some way of doing this but unfortunately didn't work :

getString = input('Please enter something : ')
# ConvertedString = set(getString)
# print(type(ConvertedString))
print(getString)


vowels = 'A', 'E', 'I', 'O', 'U'
notVowels = []

for i in getString:
    for x in vowels:
        if i == x:
            print('Sorry')

for y in getString:
    for c in vowels:
        if y not in c:
            notVowels.append(y)
            print(notVowels)

and also

def recognize_vowels(vowels, consonants):
    for i in getString:
        if vowels not in i:
            consonants = list(getString)
            print(vowels)
        return vowels
        return consonants


recognize_vowels({'A', 'E', 'I', 'O', 'U'}, getString)

After all , yet I'm unable to get the output that I want
So , I'll be very happy if you can possibly help me solving this problem .
Thanks .

[Pereskia]

In your current code:
Your first outer loop (line 10-13, second code block) writes out 'Sorry' for every uppercase vowel in your string (it ignores 'a' but catches 'A')

Your second outer loop (line 15-19) adds a letter to the list multiple times. The reason for this is the loop on line 16 which makes you examine every letter many times. Try to replace this with an 'if' statement instead testing if your character is in the vowels set or not.

In your last code block you have an error. You can use the 'in' operator with two strings to check if the first string is in the other. However, 'vowels' is not a string, you can check its type with

print(type(vowels))

.

Hope this helps you a step closer.

[perfringo]

Maybe it's good idea to clarify what you want to accomplish and based on that write some code.

As it appears:

1. Input is string
2. Output is list of consonants in input string sorted in alphabetical order
3. Set must be used

So, in process we need somehow use set. Set is unordered collection of unique elements.

In general terms our steps can be: extract unique characters from string, filter out vowels and sort result.

How to get unique characters from string? One approach can be:

>>> s = 'What a wonderful world'
>>> set(s)
{' ', 'W', 'a', 'd', 'e', 'f', 'h', 'l', 'n', 'o', 'r', 't', 'u', 'w'}

All unique characters nicely extracted. But, as one can observe, there is problem with capital letters ('W' and 'w') and space (' ') - we need to handle those in order to get correct output.

To solve capital letter(s) problem why not feed set function with lowercase string:

>>> set(s.lower())
{' ', 'a', 'd', 'e', 'f', 'h', 'l', 'n', 'o', 'r', 't', 'u', 'w'}

Nice! Now we need to filter out vowels and space. There are many ways to achieve it. It can be done with comprehension or with set method:

>>> vowels = 'aeiou'
>>> set(s.lower()).difference(set(vowels))
{' ', 'd', 'f', 'h', 'l', 'n', 'r', 't', 'w'} 

We are free of vowels but have space. We can 'cheat' and add space to vowels:

>>> vowels = 'aeiou '
>>> set(s.lower()).difference(set(vowels))
{'d', 'f', 'h', 'l', 'n', 'r', 't', 'w'}

We are getting closer. Now we need to sort. As built-in function sorted takes any iterable and returns list then we can just apply it. To be extremely concise we condense it into oneliner:

>>> sorted(set(s.lower()).difference(set('aeiou ')))                   
['d', 'f', 'h', 'l', 'n', 'r', 't', 'w']

Input is string - check
Output is list of consonants in alphabetical order - check
sets are used - check

NB! One should be aware of this behaviour:

>>> s = "It's a wonderful world"
>>> sorted(set(s.lower()).difference(set('aeiou ')))                   
["'", 'd', 'f', 'l', 'n', 'r', 's', 't', 'w']