How to make a message if there is a value error

[theguy007]

import random

secret_num = random.randrange(1, 10)

while True:
       number = int(input("Guess a number between 1 and 10: "))
       if number == secret_num:
           print("You guessed right!")
           break

I want to the program to say "You did not enter a number!" if there is a value error, for example if the user types in a letter or something else that usually makes the program shut down.  I know you can use exceptions but I just can't make it work when I try to use them. Please help a newbie programmer out 

[Larz60+]

You could use:

try:
   if number = int(input("Guess a number between 1 and 10: "))
except ValueError:
   print("Number must be an integer!")

[theguy007]

You could use:

try:
   if number = int(input("Guess a number between 1 and 10: "))
except ValueError:
   print("Number must be an integer!")

Hey, thanks for the reply. That helped a lot! My code now looks like this: 

import random

secret_num = random.randrange(1, 5)

while True:
    try:
        number = int(input("Guess a number between 1 and 5: "))
        if number == secret_num:
            print("You guessed right!")
            break

        if number > 5 or number < 1:
            print("That number is too low or high!")

        elif secret_num != number:
            print("Wrong number, try again!")

    except ValueError:
        print("That is not a number!")