Copy same doubled matched words

[kozaizsvemira]

I've been trying to figure this one out, but all I could find is people having problem with duplication instead of adding it as a feature.
I have this code below and it copies same matched words from two text files, but if there is two or more of same matched word it only copies it once. I need a function if there are two or more of the same matched words copy both of them.
Example: Analyze text1 contains(Some Random Text About Value Value Or More) text2 contains(Value Add More) code would copy 'Value' only once, I need it to copy both values so it says 'Value, Value'
Thanks to Larz60 one more time for helping me with code below.

import os
 
def get_words(filename):
    wordlist = []
    with open(filename) as fp:
        for line in fp:
            wordsinline = line.strip().split()
            for item in wordsinline:
                if item not in wordlist:
                    wordlist.append(item)
    return wordlist
 
def find_common_words(filename1, filename2):
    wordlist1 = []
    wordlist2 = []
    matching_words = []
 
    wordlist1 = get_words(filename1)
    wordlist2 = get_words(filename2)
 
    matching_words = set(wordlist1) & set(wordlist2)
    print(matching_words)
 
def testit():
    # Assert in same directory as code
    os.chdir(os.path.abspath(os.path.dirname(__file__)))
    filename1 = 'words1.txt'
    filename2 = 'words2.txt'
    find_common_words(filename1, filename2)
 
if __name__ == '__main__':
    testit()

[perfringo]

What should happen if text2 contains words which occur more than once?

My understanding is that this is counting. One could approach it:

- make set of words from text2 (performing word cleaning beforehand i.e making them same capitalization, eliminating punctuation and what not)
- using collections.Counter count occurrence of words in text1 (performing the same cleaning beforehand)
- using set operation find overlapping between keys and set and construct new dictionary from them where values are keys multiplied with counted occurrences.
- use this dictionary whichever way is needed

EDIT:

Quick expression of this idea in Python (better idea is to use string.punctuation for removing punctuation):

>>> text_1 = 'Some Random Text About Value Value Or More'
>>> text_2 = 'Value Add More'
>>> words = {word.lower().strip('.,;:') for word in text_2.split()}
>>> words
{'value', 'add', 'more'}
>>> from collections import Counter
>>> occurrances = Counter(word.lower().strip('.,;:') for word in text_1.split())
>>> occurrances
Counter({'value': 2, 'some': 1, 'random': 1, 'text': 1, 'about': 1, 'or': 1, 'more': 1})
>> result = {k: [k for occur in range(occurrances[k])] for k in words.intersection(occurrances)}
>>> result
{'value': ['value', 'value'], 'more': ['more']}

[kozaizsvemira]

Thanks for helping out, I found the solution without set since set was created to remove duplicates. I forgot to set the thread to solved. Thanks again.