How to background another process in Python?

[Kalet]

The thing is, I'm trying to get a process inside my script and have me call it whenever I want. For example, I'm filling in some data and I enter the word "background". In this way, it is called a process that is always active. I leave my code in python, I have created a decorator but I get the following error: "EOFError".

Besides that, it should work both ways, when I'm in the background and insert "background", it should return to the main function.

I share with you the code I've been doing:

#!/usr/bin/env python
# -*- coding: utf-8 -*-


import os, time

def daemonLife(func):
    def wrapper(*args, **kwargs):
        if os.fork(): return
        func(*args, **kwargs)
        os._exit(os.EX_OK)
    return wrapper

@daemonLife
def my_func():
   no_kill_nothing = "Hi!"
   print('pid of it: %d' % os.getppid())
   var2 = str(input("Inside of background!"))
   if var2 == "background":
      main(no_kill_nothing)

def main(text):
   if text == "background":
      my_func()

text = str(input("Insert something"))
main(text)

I tried multi-threading because I think it's more ideal but I haven't been able to.

Thank you very much!

[shang12]

Unless stdin is close-on-exec, the child should be able to read from it after the parent is terminated. What you are experiencing, however, is probably a conflict with the terminal's process group control and the shell's job control. When the parent dies, the shell takes back over as the foreground process of the terminal. Background processes trying to read from the terminal get a SIGTTIN. Is it explicitly requested to read from the terminal from the child process, because that seems simply a bad idea (why not keep the parent)?

I dont' sure about EOFError, you can read more at https://stackoverflow.com/questions/3479...nt-process

[newbieAuggie2019]

[ ... ] I get the following error: "EOFError".
[ ... ]

        if os.fork(): return

Hi!

Just a thought ... Your line 9:

        if os.fork(): return

shouldn't be like this?:

        if os.fork(): 
            return

As it seems the python tags eliminated the indentation, I'm going to use 'X' to mark the indentation.
So I was saying that your line 9:

XXXXXXXXif os.fork(): return

shouldn't be like this?:

XXXXXXXXif os.fork():
XXXXXXXXXXXXreturn


All the best,