Error with simple "or" statement?

[Mark17]

I'm trying to count the number of words in a sentence that include "o" or "e." Why does this count every word?

player_str = "the best player in the world was nomar garciappara"
#Enter your code below
num_o_or_e = 0
s = player_str.split()
print(player_str)
print(s)

for word in s:
    if 'o' or 'e' in word:
        print(word)
        num_o_or_e = num_o_or_e + 1
print('The number of words with an o or e in specified sentence is',num_o_or_e)

[buran]

https://python-forum.io/Thread-Multiple-...or-keyword

[Mark17]

https://python-forum.io/Thread-Multiple-...or-keyword

That makes sense.

I changed it to this:

player_str = "the best player in the world was nomar garciappara"
#Enter your code below
num_o_or_e = 0
s = player_str.split()
print(player_str)
print(s)
 
for word in s:
    if 'o' in word:
        print(word)
        num_o_or_e = num_o_or_e + 1
    elif 'e' in word:
        print(word)
        num_o_or_e = num_o_or_e + 1
    else: continue
print('The number of words with an o or e in specified sentence is',num_o_or_e)

This works, but is there an easier way that would involve restructuring only the "if 'o' or 'e'" line?

[buran]

well, the example from the link I posted:

if 'o' in word or 'e' in word:

or

if any(char in word for char in 'oe'):

or more exotic

if set('oe') & set(word):

[Mark17]

well, the example from the link I posted:

if 'o' in word or 'e' in word:

Oops... I added a second if.

Thanks!