number repeating twice in loop

[JonnyEnglish]

Hi,
can you help me understand why the number 9 repeats twice when i run this loop?

import math

digits = 123456789
reversed_numbers = []
counter = 1
for digit in range(9):
    test = (digits / (10 * counter)) % 10
    counter *= 10
    after_point = test - int(test)
    digit_after_point = int(10 * round(after_point, 1))
    print(digit_after_point)

[bobfat]

Hello,

The problem as it seems is when you use the int() function on the expression: "10 * round(after_point, 1)".

Executing the two first step of your loop, the value of "after_point" variable are so close: 0.90000 for step 1 and 0.88999 for step 2. When rounding, it will give the same value in the either cases (0.9).

[JonnyEnglish]

Thank you

[ThomasL]

for digit in range(9):

You are aware that digit iterates from 0 to 8, so 9 is not included.