how to manage an input()

[rodrigoH]

Hello, I am new to Python and was trying this code (which is used to guess the number picked by system -using the random function-) and I wanted to add some features, such as:

If the number picked by user is higher than the one picked by the random function, print "the number you picked is lower", and the same thing if it's lower (print: "it's higher").


* To be clear: I want to save (a variable) the input throught "stdin"(of type int - I know I have to cast it from str to int-), and then use this variable to keep referencing the user input to improve my code and do what I explained on the 2nd paragraph.


This is the orignal code (working ok, but with no features):

import random
secret = random.randint(0,50)

message = 'Pick a number from 1 to 49: '

even_number = (secret % 2) == 0

if even:
    print("The number is even")
else:
    print("The number is odd")

attempts = 0
MAX = 5

while int(input(message)) != secret:

    if attempts >= MAX -1:
        print("You loose")
        break
    else:
        attempts += 1
        print('No!')
else:
    print('You guessed!')

Thank you in advance!!

[jefsummers]

Something like this will get you pointed in right direction (the first part is your code)

import random
secret = random.randint(0,50)
 
message = 'Pick a number from 1 to 49: '
 
even_number = (secret % 2) == 0
 
if even:
    print("The number is even")
else:
    print("The number is odd")
 
attempts = 0
MAX = 5
found = False  
while not found:
    guess = int(input('Enter a guess: '))
    if guess == secret:
        blah
    elif guess > secret:
        blah
    elif guess < secret:
        blah