Adding loop results as rows in dataframe

[Shreya10o]

How do I make this for loop print the results as respective rows of the same dataframe. I tried this code but it doesn't seem to be working.

list2=[(('ATM',), ('ROA',)), (('ATM',), ('ROE',)), (('ATM',), ('NIM',)), (('ATM',), ('ROA', 'ROE'))]
tm_final = {0: 3, 1: 6, 2: 4, 3: 2, 4: 0}
totalrows=sum(tm_final[i]>0 for i in tm_final)
df=pd.DataFrame(columns=['A','B','C'])

for i in tm_final:
  if tm_final[i]>0:
    for j in range(totalrows):
      df.iloc[j,0]=i
      df.iloc[j,1]=str(list2[i])
      df.iloc[j,2]=tm_final[i]
    print(df)

[anbu23]

Are you expecting this output?

list2=[(('ATM',), ('ROA',)), (('ATM',), ('ROE',)), (('ATM',), ('NIM',)), (('ATM',), ('ROA', 'ROE'))]
tm_final = {0: 3, 1: 6, 2: 4, 3: 2, 4: 0}
totalrows=sum(tm_final[i]>0 for i in tm_final)
df=pd.DataFrame(columns=['A','B','C'])
 
for i in tm_final:
  if tm_final[i]>0:
      df=df.append({'A':i,'B':list2[i],'C':tm_final[i]},ignore_index=True)
      print(df)

[Shreya10o]

Are you expecting this output?

list2=[(('ATM',), ('ROA',)), (('ATM',), ('ROE',)), (('ATM',), ('NIM',)), (('ATM',), ('ROA', 'ROE'))]
tm_final = {0: 3, 1: 6, 2: 4, 3: 2, 4: 0}
totalrows=sum(tm_final[i]>0 for i in tm_final)
df=pd.DataFrame(columns=['A','B','C'])
 
for i in tm_final:
  if tm_final[i]>0:
      df=df.append({'A':i,'B':list2[i],'C':tm_final[i]},ignore_index=True)
      print(df)

Thank you! That worked. Only thing is that the print(df) should be out of the loop, so that it only prints it once.