return issue in a function

[PyPhanman]

I am trying to print the list at the end of my code. But I can't seem to figure out how to return the list when it is called inside another function.

[code]def main():
    select()
    print(list1, list2)
def select():
    select = 0
    select = int(input('Select one of the following: \n'
                   '(1) for list one \n'
                   '(2) for list two'))
    try:
        if select == 1:
            one()
        elif select == 2:
            two()
    except ValueError:
        print('try again')
def one():
    list1 = []
    list1.append(1)
    return list1
def two():
    list2 = []
    list2.append(1)
    list2.append(2)
    return list2
def print(list1, list2):
    print(list1)
    print(list2)
main()[/code]

[volcano63]

return one()

should help

[wavic]

Hello!
I don't see how this will work.
Top to the bottom.
You don't have to initialise 'select' to 0.
The input() have to be in try/except statement too. This will cause the error, not the if statement
Do not rewrite the Python's built-in functions as you did it with print(). And is meaningless because all the function does is to print something. Just like the real one. Here is a list with these built-ins.
How this rewritten print function gets its arguments. They are not global variables. This will throw a NameError.
As I see it you never create the second list because of that if statement.
main() should be defined like this

def main():
    list1, list2 = select() # but you will get "ValueError: not enough values to unpack" here
    print(list1, list2)

So the select() function has to be changed too. To return two objects. If one is populated the other could be None.