how to return False in ternary condition

[KEYS]

The code below is running inside a while True loop

if play=='y':
    print('ok')
else:
    return False

I would like to write those lines in a ternary form.
Problem with my code is it seems you cannot return in ternary conditions.

print('ok') if play=='y' else return False

Is there a way to achieve this?

[jefsummers]

Other than for style, why do you want to do that?

[MrBitPythoner]

You can achieve this with semicolons. You dont ordinarily see ; in python, but you can use them.

print("hi");print("hi again")

buran write Dec-10-2020, 05:08 AM:
Please, use proper tags when post code, traceback, output, etc.
See BBcode help for more info.

[bowlofred]

The ternary syntax is a special form of an expression, and is limited to expressions only. It isn't a full control flow like a real "if" statement. You can't put statements like "return" into those expressions.

[deanhystad]

Semicolons just make linters angry. One statement per line please. Why do people like to write dense, unreadable code?

[MK_CodingSpace]

return statement can only be used in a function, not elsewhere

[deanhystad]

return statement can only be used in a function, not elsewhere

This may or may not be a problem here. We have no context provided for the code in question. But this is invalid Python if it is in a function or not. "return" is not an expression. A ternary expression is "expression condition expression". In

answer = 'odd' if x % 2 else 'even'

'even' and 'odd' are expressions and 'if x % 2 else' is the condition.

An expression is something that evaluates to a value. A string is an expression. An equation is an expression. A function call is an expression. A "return", ironically, is not an expression because it does not evaluate to a value.

[perfringo]

Some additional tidbits. In Python there is conditional expression set forth in PEP308.

Guido in Python-Dev list:

Pleas stop calling it 'ternary expression'. That doesn't explain
what it means. It's as if we were to refer to the + operator as
'binary expression'.