Regular expression: cannot find 1st number in a string

[Pavel_47]

Hello,

Here is test string:

aaa = '   2jhjh 890 jjk'

Here is how I try to find 1st number in aaa (2 in this case):

bbb = re.match('\d', aaa)

What I finally get:

Output:
>>> type(bbb)
<class 'NoneType'>

Any suggestions ?

Thanks.

[Pavel_47]

Here is a solution using search:

bbb = re.search('\d', aaa).group()

So, match can't be used for this task ?

[bowlofred]

Correct. Let's look at the description of match.

match(pattern, string, flags=0)
Try to apply the pattern at the start of the string, returning
a Match object, or None if no match was found.

match() is as if your pattern has an implicit ^ anchoring to the beginning of the string. search() doesn't and can look elsewhere in the string.