Why are two variables unequal as they point to the same value?

[fc5igm]

>>> girl
<_io.TextIOWrapper name='D:\\python\\works\\girl_3.txt' mode='w' encoding='cp936'>
>>> fgirl3
<_io.TextIOWrapper name='D:\\python\\works\\girl_3.txt' mode='w' encoding='cp936'>
>>> girl==fgirl3
False

The process of how the variables were given the values:

f=open(r'D:\python\works\record.txt')
fboy1=open(r'D:\python\works\boy_1.txt','w')
fboy2=open(r'D:\python\works\boy_2.txt','w')
fboy3=open(r'D:\python\works\boy_3.txt','w')
fgirl3=open(r'D:\python\works\girl_3.txt','w')
fgirl2=open(r'D:\python\works\girl_2.txt','w')
fgirl1=open(r'D:\python\works\girl_1.txt','w')
for num in range(3):
    boy=[fboy1,fboy2,fboy3][num]
    girl=[fgirl1,fgirl2,fgirl3][num]

(I tried to insert the codes as code, but it's a failure when I clicked the referred button.)

buran write Jun-08-2021, 01:39 PM:
Please, use proper tags when post code, traceback, output, etc. This time I have added tags for you.
See BBcode help for more info.

[Gribouillis]

Each call to open() creates a new instance of _io.TextIOWrapper. By default, Python objects compare equal if they are the same instance. The equality between open files objects has not been defined as the equality of the files' contents.

[snippsat]

You are comparing file-object and not the actual value.
file-object create new instance and will be False as it's stored in different memory addresses.
Example.

boy = 'Kent'
fboy1 = open(r'boy_1.txt', 'w')
fboy1.write(boy)
fboy2 = open(r'boy_2.txt', 'w')
fboy2.write(boy)
fboy1.close()
fboy2.close()

boy_1 = open('boy_1.txt')
boy_2 = open('boy_1.txt')

Test

>>> boy_1
<_io.TextIOWrapper name='boy_1.txt' mode='r' encoding='UTF-8'>
>>> boy_1 == boy_2
False
>>> # Now read file-object and compare actual value
>>> boy_1.read()
'Kent'
>>> boy_1.read() == boy_2.read()
True

Advisable is when read/write is to use with open()(no need to close file-object),
and your encoding is strange(cp936) as OS guess wrong(always utf-8) or Unicode can be wrong.
Here a example of this.

boy = 'Tom'
test_uni = '教えてもらった'
with open('b1.txt', 'w', encoding='utf-8') as f_out:
    f_out.write(f'{boy}\n')
    f_out.write(test_uni)

with open('b1.txt', encoding='utf-8') as f:
    print(f.read())

Output:
Tom
教えてもらっ

[fc5igm]

You are comparing file-object and not the actual value.
file-object create new instance and will be False as it's stored in different memory addresses.
Example.

boy = 'Kent'
fboy1 = open(r'boy_1.txt', 'w')
fboy1.write(boy)
fboy2 = open(r'boy_2.txt', 'w')
fboy2.write(boy)
fboy1.close()
fboy2.close()

boy_1 = open('boy_1.txt')
boy_2 = open('boy_1.txt')

Test

>>> boy_1
<_io.TextIOWrapper name='boy_1.txt' mode='r' encoding='UTF-8'>
>>> boy_1 == boy_2
False
>>> # Now read file-object and compare actual value
>>> boy_1.read()
'Kent'
>>> boy_1.read() == boy_2.read()
True

Advisable is when read/write is to use with open()(no need to close file-object),
and your encoding is strange(cp936) as OS guess wrong(always utf-8) or Unicode can be wrong.
Here a example of this.

boy = 'Tom'
test_uni = '教えてもらった'
with open('b1.txt', 'w', encoding='utf-8') as f_out:
    f_out.write(f'{boy}\n')
    f_out.write(test_uni)

with open('b1.txt', encoding='utf-8') as f:
    print(f.read())

Output:
Tom
教えてもらっ

Thank you

[fc5igm]

Each call to open() creates a new instance of _io.TextIOWrapper. By default, Python objects compare equal if they are the same instance. The equality between open files objects has not been defined as the equality of the files' contents.

Thank you