list comprehension with regular expression

[aibrain]

Wanted to do something like this:
# get rid of negative values for age

raw={'name': ['a', 'b', 'c', 'd', 'e'], 'age': [20,21,-1,22,-1]}
data=pd.DataFrame(raw)
cdata=pd.DataFrame()
cdata=data[data['age'] > 0]
print(cdata)

output:
   age name
0   20    a
1   21    b
3   22    d

but with str (couldn't so ended up with this):
# get rid of names with digits

raw={'name': ['a', '3', 'c', 'd', 'e'], 'age': [20,21,20,22,21]}
data=pd.DataFrame(raw)
cdata=pd.DataFrame()
j=[]
for i in data.index:
    j.append(not bool(re.search(r'\d',str(data.ix[i]['name']))))
cdata=data[j]
print(cdata)

any ideas how to do this without a loop OR another faster way?

[zivoni]

data[~data.name.str.contains(r"\d")]

you dont need to create empty dataframes.