passing php variable to python file

[jerald]

I have a php file that pass file name as string variable to python. And once the python receive the string variable it will open the file based on the string variable.

python file

#!C:\Python\Python39\python.exe
print ('Content-type: text/html\n\n')
import sys
print(sys.argv)
filename = sys.argv[1]
print(filename)

with open(filename+'.py', 'r') as inFile:
  print(inFile.read())

php file

$filename = "stringfile";
$command = "python receivephpvariable.py  \"$filename\"";
echo $command ;
 echo shell_exec($command);

but i got the error :

Error:
['c:\\xampp\\htdocs\\project_real\\receivephpvariable.py']
Traceback (most recent call last):
  File "c:\xampp\htdocs\project_real\receivephpvariable.py", line 5, in <module>
    filename = sys.argv[1]
IndexError: list index out of range

[Larz60+]

I haven't used PHP for quite a while, but don't you need to index line 4 of the php to return first value?