[SOLVED] Simplify condition test in if block?

[Winfried]

Hello,

Out of curiosity, is there a way to simply an "if" line with multiple conditions?

if status == "1" \
	or status == "2" \
	…
	or status == "37":
		print("Yes")

Thank you.

[bowlofred]

You could check if status matches an element in a collection.

if status in ["1", "2", "37"]:
    print("Yes")

Lists are fine for small collections. If the number of choices got to be too large, the lookup speed of a dict or a set might be useful.

[Winfried]

Nice.

Since the values are actually a long list of strings, I used a set:

status_set = {"String 1","String 3","String 4",\
		"String 5"}

if status in status_set:
	print("Hit!")

Thanks!