Encrypt and decrypt in python using own fixed key

[SriRajesh]

Hi I want to encrypt an d decrypt. But I want to use fixed defined key for example: key = "Abcd123". Can some one help how to do it. Thanks in advance. I use below code.

from cryptography.fernet import Fernet
message = "I am python" 
key = Fernet.generate_key()
fernet = Fernet(key)
encMessage = fernet.encrypt(message.encode())
print("original string: ", message)
print("encrypted string: ", encMessage)
decMessage = fernet.decrypt(encMessage).decode()
 
print("decrypted string: ", decMessage)

[dboxall123]

Hi. I can't say that I've ever used the cryptography module, but I got this and modified this from the cryptography website:

import base64
import os
from cryptography.fernet import Fernet
from cryptography.hazmat.primitives import hashes
from cryptography.hazmat.primitives.kdf.pbkdf2 import PBKDF2HMAC
salt = os.urandom(16)
kdf = PBKDF2HMAC(
    algorithm=hashes.SHA256(),
    length=32,
    salt=salt,
    iterations=390000,
)
message = b"I am python"
password = b"Abcd123"
key = base64.urlsafe_b64encode(kdf.derive(password))
f = Fernet(key)
encMessage = f.encrypt(message)
print(encMessage)
decMessage = f.decrypt(encMessage)
print(decMessage.decode('utf-8'))

[SriRajesh]

Hi. I can't say that I've ever used the cryptography module, but I got this and modified this from the cryptography website:

import base64
import os
from cryptography.fernet import Fernet
from cryptography.hazmat.primitives import hashes
from cryptography.hazmat.primitives.kdf.pbkdf2 import PBKDF2HMAC
salt = os.urandom(16)
kdf = PBKDF2HMAC(
    algorithm=hashes.SHA256(),
    length=32,
    salt=salt,
    iterations=390000,
)
message = b"I am python"
password = b"Abcd123"
key = base64.urlsafe_b64encode(kdf.derive(password))
f = Fernet(key)
encMessage = f.encrypt(message)
print(encMessage)
decMessage = f.decrypt(encMessage)
print(decMessage.decode('utf-8'))

It show error:
TypeError:__init__() missing 1 positional argument:'backend'

[dboxall123]

It's working perfectly here. Post the complete error.