[Tkinter] filedialog, open a file error

[liketocode]

Hello

I would like to know how to avoid an error when i close the window instead of choosing a file to open.
Window that show after clicking on "open" button.

from tkinter import *
from tkinter import filedialog

def openFile():
    filepath = filedialog.askopenfilename(initialdir="C:\\Test",
                                          title="Open file okay?",
                                          filetypes=(("text files", "*.txt"),
                                          ("all files", "*.*")))
    file = open(filepath, 'r')
    print(file.read())
    file.close()

window = Tk()
button = Button(text="Open",command=openFile)
button.pack()
window.mainloop()

Error:
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Papa Smurf\AppData\Local\Programs\Python\Python37\lib\tkinter\__init__.py", line 1705, in __call__
    return self.func(*args)
  File "C:/Users/Papa Smurf/PycharmProjects/Pythonbasics/test/open1.py", line 9, in openFile
    file = open(filepath, 'r')
FileNotFoundError: [Errno 2] No such file or directory: ''

[deanhystad]

Check the filepath. It will be an empty str if no file is selected.

You should answer these kinds of questions yourself. All you needed to do is set a breakpoint on line 9 and display what is returned when you cancel the file dialog. Or you could use a print statement, or you could read the documentation for the tkinter file dialog. Any of these would show you that the len(filepath)==0 when the selection is canceled.

def openFile():
    filepath = filedialog.askopenfilename(title="Open file okay?")
    print(len(filepath))

window = Tk()
button = Button(text="Open",command=openFile)
button.pack()
window.mainloop()

Output:
0
63

To get this output I canceled the first selection and selected a file the second time around.

[liketocode]

Gee...Thx ! I'm still begginer so i miss things that are so obvious

def openFile():
    filepath = filedialog.askopenfilename(initialdir="C:\\Test",
                                          title="Open file okay?",
                                          filetypes=(("text files", "*.txt"),
                                          ("all files", "*.*")))
    if len(filepath) == 0:
        return

    file = open(filepath, 'r')
    print(file.read())
    file.close()

[deanhystad]

It is exactly because you are a beginner that doing little experiments to try to understand what is happening is so important. If you dive in and figure things out for yourself your learning will progress at a much faster pace.

[liketocode]

Agree