How to get the color name of qlistwidget?

[flash77]

Hi,

I'm trying to get the color name of the current item's foreground of a qlistwidget.

To set it I used:

self.listbox_medium.insertItem(0, "paper")
self.listbox_medium.item(0).setForeground(QColor("blue"))

To get the color name I tried:

    def button_apply_selection_clicked(self):
        if self.listbox_medium.currentItem().foreground().color().colorNames() == QColor("blue"):
            print("okay")
        else:
            print("bad")

In the listbox (qlistwidget) I've got 2 items:
one with a blue foreground,
one with a green foreground.

But if I try to check for "blue" or "green", it is always returned "bad"...

I couldn't find the correct syntax for checking for the color names...

Could you please give me a hint?

Thanks a lot...

[deanhystad]

You could comapare color objects.

Output:
if self.listbox_medium.currentItem().foreground().color() == QColor("blue"):

colornames() is not going to be useful. It returns a list of all colornames that Qt knows about. The list has nothing to do with any particular color.

[Axel_Erfurt]

Maybe it's easier with hex

import sys
from PyQt5.QtWidgets import QApplication, QWidget, QListWidget, QVBoxLayout, QListWidgetItem
from PyQt5.QtGui import QColor


class Ui_MainWindow(QWidget):
    def __init__(self, parent = None):
        super(Ui_MainWindow, self).__init__(parent)
        self.window = QWidget()
        self.listWidget = QListWidget()
        self.window.setWindowTitle("ListWidget")
        
        self.listWidget.currentItemChanged.connect(self.index_changed)

        listWidgetItem = QListWidgetItem("Hello World")
        listWidgetItem.setForeground(QColor("#0000ff")) # blue
        self.listWidget.addItem(listWidgetItem)
        
        listWidgetItem = QListWidgetItem("Hello World")
        listWidgetItem.setForeground(QColor("#ff0000"))
        self.listWidget.addItem(listWidgetItem)
        
        self.listWidget.setCurrentRow(1)

        window_layout = QVBoxLayout(self.window)
        window_layout.addWidget(self.listWidget)
        self.window.setLayout(window_layout)
        self.window.show()
            
    def index_changed(self, item):
        if item.foreground().color().name() == "#0000ff": # blue
            print("is blue")
        else:
            print("is not blue")

if __name__ == '__main__':
    app = QApplication(sys.argv)
    win = Ui_MainWindow()
    sys.exit(app.exec_())

[deanhystad]

Doesn't matter if you use the color name, or RGB.
from PySide6.QtGui import QColor
print(QColor("blue") == QColor("blue"))
print(QColor("blue") == QColor("red"))
print(QColor("blue") == QColor("#0000ff"))

Output:
True
False
True

Either way in is a bad idea using color as a state.

[Axel_Erfurt]

Yes, but item.foreground().color().name() returns hex color.

[flash77]

Dear deanhystad,
dear Axel_Erfurt!!

Thanks a lot for your answers, it helped me much...