convert to bin problem

[kucingkembar]

hi, sorry for my bad english,
i tried to create phash compare using "VideoHash"

#pip install videohash
from videohash import VideoHash
import time
start_time = time.time()
path = "input.mp4"
a = VideoHash(path=path)
print(a)
print(type(a))
b = str(a)
print(b)
print("len :",len(b))
print(type(b))
c = int(b,2)
print(c)
print(type(c))
d = bin(c)
print(d)
print("len :",len(d))
print(time.time() - start_time,"Seconds")

and the result:

Output:
0b0000100100001110111000100111111101100001011000010100000000000000
<class 'videohash.videohash.VideoHash'>
0b0000100100001110111000100111111101100001011000010100000000000000
len : 66
<class 'str'>
652708032737787904
<class 'int'>
0b100100001110111000100111111101100001011000010100000000000000
len : 62
9.695210933685303 Seconds

but the number of digits after conversion is different, the original is 66, and the converted is 62,
i tried to using format( '#064b') but it for string data,
i need it because the binary needs to compare using a bitwise technique

def hamming_distance(a, b):
  return bin(a ^ b).count('1')
print(hamming_distance(a, b))

please help me

[Gribouillis]

Conversion to int removed the zeros at the beginning. You could simply add a 1 at the beginning

s = '1'+ a[2:]
c = int(s)

[kucingkembar]

Conversion to int removed the zeros at the beginning. You could simply add a 1 at the beginning

s = '1'+ a[2:]
c = int(s)

thank you for the reply,
the main problem, the standard is 64-bit data,
it can be stated at 0b00, to 0b11
and the target is bin(ary) for bitwise operation

[kucingkembar]

ok, i solve it by split it by chars

for i in range(2,len(str(a))):
    print(str(a)[i])