[closed] check whether an integer is 32 or 64 bits

[paul18fr]

Hi,

A basic question: how to check if the variable t1 is wheter a 32 bits integer or 64 one? Natively I've been thinking its a 32 bits but I've not so sure.

Thanks

import numpy as np

t = 2.0

t1 = int(t)
print(f"t1 = {type(t1)}")


t2 = np.int32(t)
print(f"t2 = {type(t2)}")

t3 = np.int64(t)
print(f"t3 = {type(t3)}")

[snippsat]

Python's native int type is unbounded,meaning it can grow as large as the memory allows.
NumPy has fixed bit-width like eg int32 or int64 and also int8, int16.
Can use .bit_length() to check both standard Python and NumPy(has no own bit_length() check).

>>> t1 = 30
>>> t1.bit_length()
5
>>> t2 = np.int32(t)
# Convert to int to use bit_length()
>>> int(t2).bit_length()
5

So if go over max of 32bit(2147483647),will get a error as should in NumPy

>>> t = 2147483648
>>> t.bit_length()
32
>>> t2 = np.int32(t)
Traceback (most recent call last):
  File "<interactive input>", line 1, in <module>
OverflowError: Python int too large to convert to C long

# As mention standar int is unbounded
>>> t = 21474836480000000000000000000000000000000000000000000000000000000000000000000000000000000000
>>> t.bit_length()
304

[deanhystad]

t1 is an int, not 32 or 64. int does not have a size.

[paul18fr]

I got it, thanks

[deanhystad]

did you see this?

https://www.youngwonks.com/blog/Coding-o...and-PyGame