How to run shell command, capture the output, then write it into textfile?

[tatahuft]

How to run shell command, capture the output, then write it into textfile?

I tried to use code below:

from subprocess import run


data = run("cstool arm64 1F2003D5", capture_output=True, shell=True, text=True)

print(data.stdout)


hfile3 = open("result1.txt", "a")

hfile3.write(data.stdout())

hfile3.close()

It can successfully print what I want, but it cannot write into text file


there is error message: 'str' object is not callable

How can I capture / assign the stdout result into a variable as string?

Can I do something like:

Result = data.stdout()?

Thank You

[tatahuft]

I think I got the answer,
hfile3.write(data.stdout)
Thank You

[paul18fr]

I've ever used something like the following snippet that writes in the txt file what the shell prints

import os, subprocess

Path = os.getcwd()  
txtFile = 'mytxt.txt' 
shellName = 'xxx.sh'
     
with open (Path + '/' + txtFile, 'a') as f:
    command_line = f"sh {shellName}"
    args = command_line.split()
    process = subprocess.run(args, stdout=f, text=True)

[tatahuft]

I've ever used something like the following snippet that writes in the txt file what the shell prints

import os, subprocess

Path = os.getcwd()  
txtFile = 'mytxt.txt' 
shellName = 'xxx.sh'
     
with open (Path + '/' + txtFile, 'a') as f:
    command_line = f"sh {shellName}"
    args = command_line.split()
    process = subprocess.run(args, stdout=f, text=True)

Thank You

I'll try it

[Axel_Erfurt]

another version

from subprocess import check_output
 
txt_file = 'shell_output.txt' 
shell_command = 'ls ./'
      
with open (txt_file, 'a') as f:
    shell_output = check_output(shell_command, shell=True)
    f.write(shell_output.decode())