int(variable) not changing variable to an integer

[StoopidChicken]

For whatever reason the below code runs the command int(ans), but ans is not an integer when checked.

def intCheck(num):
    try:
        int(num)
        return True
    except:
        return False

def redo():
    ans = input('Input an integer: ')

    if intCheck(ans) == True:
        int(ans)
        print('Answer has been turned into an integer')
    else:
        print('You did not input an integer')

    if isinstance(ans, int):
        print('\nIt worked')
        redo()
    else:
        print("\nIt didn't work")
        redo()

redo()

This code also doesn't work, so the check can't be the problem.

ans = '1'
int(ans)

if ans == 1:
    print('It worked')
else:
    print("It didn't work")

The only other thing I can think of is ans might be a prohibited variable name, but I've changed it and the code still doesn't work.
I'm using python 3.6.3. Would appreciate any help if you know what's wrong, thanks.

[Gribouillis]

If you want to turn ans into an integer, you need to write

ans = int(ans)

However, why not simply write

try:
    ans = int(ans)
except TypeError:
    print("You didn't enter an integer.")
else:
    print("You entered an integer.")

? This avoid a type-checking function.

[StoopidChicken]

Thank you, completely forgot about that.

---

However, why not simply write

try:
    ans = int(ans)
except TypeError:
    print("You didn't enter an integer.")
else:
    print("You entered an integer.")

? This avoid a type-checking function.

That works just as well, I've gotten into the habit of making a function in case I want to check multiple times. I just find it easier.