Very basic programming help needed: pig latin program

[bstocks]

VOWELS = ('a','e','i','o','u','A','E','I','O','U')
word = input("Welcome to the Pig Latin translator, simply enter a word and the translator will return the word in Pig Latin. Insert your word below. \n> ")

def pigLatin(word):
    if word[0] in VOWELS:
        print (word + 'ay')
    else:
        print (word[1:] + 'ay')
pigLatin(word)

playAgain = input("Would you like to play again? \n> ")

def secondGame(playAgain):
    if playAgain == ('yes'):
        second = input("Enter your next word below \n> ")
        pigLatin(second)
    elif playAgain == ('no'):
        print ('Thanks for playing!')
    else:
        print ('Error: Please respond with a yes or no answer.')

secondGame(playAgain)

________________________________________________________________________________________________

Above is my code. It runs fine. I basically just had it run through a second time using the secondGame function I made. This still ends the game after only two words have been entered (if you choose the yes option to play again). 

My question is - What would be a better way to loop this program? I want it to continue allowing me to enter words into the program until I tell the program "no" - I do not want to play again. 

Please help!

Thanks,
bstocks

[ichabod801]

You want a while loop. Something like:

play_again = 'yes'
while play_again == 'yes':
    # pig latin code
    play_again = input('Would you like to play again (yes or no)? ')

[RickyWilson]

def translate(text):
    return ' '.join('{}{}{}'.format(word, word[0], 'say')[1:] for word in text.split())

while 1:
    word = input('Enter some words: ')
    if word == 'quit':
        break
    print(translate(word))