copy files from one destination to another by reading filename from csv

[Prince_Bhatia]

hi,

i want to move several file mentioned in csv to another folder path which is mentioned in code

i have several pdf's mentioned in the attached csv file, in csv file there is one column with the filename including it's path....but when i try to run this it says

Error:
File "C:\Users\prince.bhatia\Desktop\install\copying_module.py", line 10
    "filename", "D:\maharera", "D:\maharera\copy" = argv[1:]
       ^
SyntaxError: can't assign to literal
[Finished in 0.226s]

below is my code:

import shutil
import os
import csv
import sys

dataobj = {}
filename = "maharera.csv"


def main(argv):
    filename, "D:\maharera", "D:\maharera\copy" = argv[1:]
    with open(filename, "rb")as csvfile:
        reader = csv.reader(csvfile)
        for row in reader:
            filename = row[0]
            filepath = row[1]

            if filename.startswith("D:\maharera"):
                filename = filename[len(existing_path_prefix):]

            newfile = os.path.join("D:\maharera\copy", filepath)
            print ('Copying %s to %s...' % filename, new_filename),
            shutil.copy(filename, new_filename)
if __main__ == "__main__":
    main(sys.argv)
#source = os.listdir("D:\maharera")
#print(source)
#destination = "D:\maharera\copy"

#for files in source:
#    if files.endswith(".pdf"):
#        shutil.copyfile(files, destination)

can anyone guide me in right direction since i have 15000 pdf out of which in files i have mentioned 501 which needed to move to another folder

[Larz60+]

Not sure what you're trying to accomplish here:

    filename, "D:\maharera", "D:\maharera\copy" = argv[1:]

did you mean:

    filename = argv[1]

What does argv look like?
also, something has changed as line number and code don't match
this statement:

if __main__ == "__main__":

needs to be:

if __name__ == '__main__':

[Prince_Bhatia]

ok what i am trying to do is ...writing a module that will read csv , pick file names from there look into the directory where these files resides and then move them to the destination folder...i think i had some error in the above code..i have redone the same code..

but now it says

Error:
no file path or directory "filepath"

below is the code

import os
import shutil
import csv
import sys

csv_file = "maharera.csv"
existing_path_prefix = "D:\maharera"
new_path_prefix = "D:\movement"

def main(argv):
  # TODO: this should do some error checking or maybe use optparse
  csv_file, existing_path_prefix, new_path_prefix = argv[1:]

  with open(csv_file, 'r') as f:
    reader = csv.reader(f)
    for row in reader:
      # Assuming the column in the CSV file we want is the first one
      filename = row[0]
      filepath = row[1]

      if filename.startswith(existing_path_prefix):
        filename = filename[len(existing_path_prefix):]

      new_filename = os.path.join(new_path_prefix, filename)

      #print ('Copying %s to %s...' % filename, new_filename),
      #print ('Copying %s to %s...' % filepath, new_filename)  #Changed
      shutil.copy(filepath, new_filename)   #Changed
      print ('done.')
#print ('All done!')


if __name__ == '__main__':
  main(sys.argv)

i read the code here...https://stackoverflow.com/questions/29850220/read-filenames-from-csv-and-then-copy-the-files-to-different-directory

please help me to correct this code so that i can move selected files which are mentioned in csv to new directory...i have attached new cvs file for this code also by editing the original post..

[Prince_Bhatia]

hi finally,i have found the soultion..this below code will do above mentioned:

import os
import shutil
import csv
import sys

csv_file = "maharera.csv"
existing_path_prefix = "D:\maharera"
new_path_prefix = r"D:\new_movement"

with open(csv_file, 'r') as f:
    reader = csv.reader(f)
    for i, row in enumerate(reader):
        if i == 0:
            print(i)
            pass    # Skip header row
        else:
            filename, filepath = row
            new_filename = os.path.join(new_path_prefix, filename)
            old_filename = os.path.join(filepath, filename)
            shutil.copy(old_filename, new_filename)