I have an array, how can I search a seperate file for the contents of my array?

[Mr_Keystrokes]

I have an array (list), how can I search a separate file for the presence of elements that are in my array?

I wanted to use python to do it instead of bash because python is where it's at these days, right?

I have collected a set of strings in my array.
I am now trying to search a file for the presence or absence of my strings in the file.

#!/usr/bin/python

import re

with open("/home/all_genera.txt") as file:

generaA=[]

    for line in file:
        line=line.strip('\n')
        generaA.append(line)

joiner='|' .join(generaA)

re.findall(joiner, open("/home/config/config2.cnf", 'r'), re.M ).read()

When I run this script the following is returned:

`File "/home/miniconda3/lib/python3.6/re.py", line 222, in findall
return _compile(pattern, flags).findall(string)
TypeError: expected string or bytes-like object`

Does occur because array elements are bytes that cannot be compared to strings?

---

Previously I had this:

#!/usr/bin/python

with open("/home/all_genera.txt") as file:

    generaA=[]

    for line in file:
        line=line.strip('\n')
        generaA.append(line)


#print (generaA)

with open("/home/config2.cnf") as config_file:
    counter = 0
    for line in config_file:
        line=line.strip('\n')

        for part in line .split():
            if generaA[counter]in part:
                print (generaA[counter], "is -----> PRESENT")
            else:
                print (generaA[counter], "is ABSENT")
    counter += 1

But this doesn't cycle through my entire array on each line, instead it checks whether only the first element is in any of the lines of the file.