Which of the following is true about local variables?

Which of the following is not the scope of a variable?

name=”Python”

def func():

    name=”PythonGeeks”

print(name)

• Which of the following is a built-in variable?

n=4

def f1():

    n=n**4

    print(n)

f1()

• Which keyword is used to reflect the changes done in the nested function at the outer function?

n=6

def fun1():

    n=4.5

    def fun2():

        global n

        n=3.2

    fun2()

fun1()

print(n)

Which of the following coding blocks does not give an error?

a.

def f1():

    def f2():

        global m

        m=3

    f2()

    print(m)

f1()

b.

def f1():

    def f2():

        global m

        m=3

    print(m)

f1()

c.

def f1():

    def f2():

        m=3

    f2()

    print(m)

f1()

d.

def f1():

    def f2():

        global m

        m=3

    f2()

    Print(m)

f1()

Which of the following is the output of the following code?

def func1():
    num=12
    def func2():
        nonlocal num
        num=7
    func2()
func1()
print(num)

x=4

def fun():

    a=4

    global x

    x=4

    print(a)

fun()

n=3

def fun1():

    global n=1

fun1()

print(n)

What is the scope of the nested functions?

def fun():

    x=x+1

    print(x)

x=12

print(x)

Which of the following coding blocks gives the output as “Python”?

a.

def fun1():

    name=”a”

    def fun2():

        nonlocal name

        name=”PythonGeeks”

    fun2()

    print(name)

fun1()

b.

def fun1():

    name=”a”

    def fun2():

        nonlocal name

        name=”PythonGeeks”

    print(name)

fun1()

c.

def fun1():

    name=”a”

    def fun2():

        name=”PythonGeeks”

    fun2()

    print(name)

fun1()

d.

def fun1():

    name=”a”

    def fun2():

        nonlocal name=”PythonGeeks”

    fun2()

    print(name)

fun1()

What is the output of the following code?

def fun1():
    name=”a”

print(fun1())
print(name)